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(1/5)*(3*x^2-(6*x)) = 0
(1/5)*(3*x^2-6*x) = 0
1/5*(3*x^2-6*x) = 0
3*x^2-6*x = 0
3*x*(x-2) = 0
x-2 = 0 // + 2
x = 2
3*x*(x-2) = 0
1/5*3*x*(x-2) = 0
( 1/5 )
1/5 = 0
x belongs to the empty set
( 3*x )
3*x = 0 // : 3
x = 0
( x-2 )
x-2 = 0 // + 2
x = 2
x in { 0, 2 }
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